Solve y 3x 5

5x 4 3x 5 3. 5x 4y 3.

Subtract 5 from both sides.

Solve y 3x 5. Steps for Solving Linear Equation. Y 3 x 5. Swap sides so that all variable terms are on the left hand side.

Swap sides so that all variable terms are on the left hand side. 3 x 5 y. Add 5 to both sides.

Add 5 to both sides. Subtract 5 from both sides. Subtract 5 from both sides.

3 x y 5. Divide both sides by 3. Divide both sides by 3.

Frac 3x 3frac y-5 3 3 3 x 3 y 5. Dividing by 3 undoes the multiplication by 3. Y 3x 5 y 3 x 5.

Use the slope-intercept form to find the slope and y-intercept. Tap for more steps. The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept.

Y m x b y m x b. Find the values of m m and b b using the form y m x b y m x b. M 3 m 3.

Steps for Solving Linear Equation. Y 3 x 5. Swap sides so that all variable terms are on the left hand side.

Swap sides so that all variable terms are on the left hand side. 3 x 5 y. Subtract 5 from both sides.

Subtract 5 from both sides. Solution for Y3x-5 equation. Simplifying Y 3x -5 Reorder the terms.

Y -5 3x Solving Y -5 3x Solving for variable Y. Move all terms containing Y to the left all other terms to the right. Solution for y3x5 equation.

Simplifying y 3x 5 Reorder the terms. Y 5 3x Solving y 5 3x Solving for variable y. Move all terms containing y to the left all.

That means take the original equation and plug in zero for y. Then solve for x and get 53. That is the x intercept.

-5 To find three points plug in another value for x. You already have two points the y-intercept 0-5 and the x-intercept 530. Plug in one more value for x or y.

So your third point. 1 y3x5 2 y2x5 Step2. 3 3xy5 4 2x-y -5 Step 3.

Add the equations 5 5x0 Step 4. 6 x0 Step 5. Substitute Equation 6 in Equation 1.

Y3x5 y30 5 y0 5 y5 Solution. Substitute the values of x and y in Equation 2. Y 2x5 5 20 5 5 05 55.

As they share the same values you can equate them to other through y in that. 3x-5 y -2x-15 Collecting terms we have 3x2x5-15 5x-10 x-2 Substitute x-2 into any of the original equations to find the value of y y3x-5 - y3-2-5 y-6-5 y-11 colorblueSo point of intersection -xy–2-11. Rep gems come when your posts are rated by other community members.

Report Thread starter 1 year ago. 3x 5 4x² x. 12 1314 23 22.

X1 x2 Simplify Example 2x22y x5 y3 Evaluate Example yx21 Graph Example 4x22 x6 Solve Example Algebra Calculator is a calculator that gives step-by-step help on algebra problems. See More Examples. Given a pair of linear equations such that 3x y 5.

1 5x - y 11. 2 To solve it by substitution method. Fron eqn 1 we have y 3x -5.

Now substituting this value in eqn 2 we get. 5x - 3x-5 11 5x - 3x 5 11. 2x 11-5.

Pair of Linear Equations in Two Variables. Algebraic Solution of a Pair of Linear Equations. X - y 53x 2y.

We solve the systems of equation by substitution method. First we solve the equation y 3x5 y 3 x 5 for x x. Then we substitute the resulting value of x.

Solve Using the Square Root Property. Convert to a Mixed Number. Convert to a Decimal.

Cube root of 125. Convert to a Simplified Fraction. Start by labelling the equations.

Y 3x 5. 5x 4y 3. Substitute equation 1 into equation 2.

5x 4y 3. 5x 4 3x 5 3. Tap for more steps.

The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. Y m x b y m x b. Y 2 3 x 5 y 2 3 x - 5.

Y 2 3x 5 y 2 3 x - 5. Use the slope-intercept form to find the slope and y-intercept. Then use that in either equation to solve for the second variable.

Solve the first for y in terms of x. Add 3x to both sides. 4y3x5 Divide both sides by 4.

Substitute that in for Y in the second equation. 34x 3x54 - 4 Solve for X. First multiply all factors by 4.

2x y 5I 3x 2y 11II Multiplying I with 2 we get. 4x 2y 10III Adding II with III 7x 21. Putting the value of x in I we get.

2 3 y 5 6 y 5 y1. See 8 pages 3x y 5 solve for y answer in Google Sheet format. Simple and best practice solution for Y3x-5 equation.

Cancel the common factor. 3x2y5 solve for y Please help I dont understand. Read also study and 3x y 5 solve for y Gii cc bi ton ca bn s.

3x - y 5. II Adding I and II. X 2.

Putting the value of x in I 2 x 2 y 5. 4 y 5. Y 1.

2x y -5. And for every y replace it with 3x y 3x. Our first equation now becomes.

2x 3x -5. Combined the similar terms on the left side and you get. Isolate x by dividing the both sides by 5 and you get.

Any time you can isolate a variable x or y in one equation you can substitute that result into the other equation to solve it.